Solving good ol' Ax=b:
>>> import numpy as np
>>> A = np.matrix('[3 -1 1; -1 1 -1; 1 -1 3]')
>>> A
matrix([[ 3, -1, 1],
[-1, 1, -1],
[ 1, -1, 3]])
>>> b = np.matrix('[1;1;1]')
>>> from scipy import linalg
>>> x = linalg.solve(A,b)
>>> x
array([[ 1.],
[ 3.],
[ 1.]])
See docs:
numpy.linalg.solve
routines.linalg
numpy solve examples (prob better than above!)
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